If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-4x^2-40x+12=0
a = -4; b = -40; c = +12;
Δ = b2-4ac
Δ = -402-4·(-4)·12
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-16\sqrt{7}}{2*-4}=\frac{40-16\sqrt{7}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+16\sqrt{7}}{2*-4}=\frac{40+16\sqrt{7}}{-8} $
| 2(x)=12-2x | | -4(x)=-2x+9 | | 2|3y-1|=16 | | -3y+10=-4(y-2) | | 8x-4=8x+7 | | 5f=15-4 | | 500=n/2(12n) | | -2/3+5/4=-3x+13/6 | | -2/3+5/4=-3x+21/6 | | 18+y=93 | | 25x+3=9 | | 3t=4(t-1) | | e^2+2e=-8 | | d^2-5d=-14 | | 3t=4t-4 | | c^2+4c=-21 | | 2x-8=-3x-43 | | b^2-7b=+10 | | 2x+12=0x+6 | | -2(3x+5)+10x=5-2x | | a^2+8a=+15 | | 2/3·(8-1/x)=2 | | d^2-3d=-40 | | 2n+7=3n+27 | | a^2+9a=-22 | | 5y+35=3(y+5) | | x=0.003(1-x) | | x/(1-x)=0.003 | | {5x+7}={3x-2} | | X3+15x2-450=0 | | 4v+8=15v-3v | | z^2-3z=+2 |